w ciągu geometrycznym dane są a1=32 a4=-4 jaki jest iloraz?
a1 = 32 , a4 = -4
q = an/a(n-1)
a4 = a1 *q^3
q^3 = a4/a1 = -4/32 = -1/8
q = -1/2
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a1 = 32 , a4 = -4
q = an/a(n-1)
a4 = a1 *q^3
q^3 = a4/a1 = -4/32 = -1/8
q = -1/2
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