W 14,2 g tlenku fosforu (V) P4010 fosfor stanowi
A 1,5g
B 3,1 g
C 4,6 g
D 6,2 g
A 1,5g
B 3,1 g
C 4,6 g
D 6,2 g
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284g P4O10-------4*31g fosforu
14,2g P4O10--------xg fosforu
x=6,2g fosforu
Odp. D 6,2 g