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l= 1/4*2πr=1/4*2π*30cm=15πcm
Obwód tarczy zegara = obwód okręgu=2πr
1/4 obwodu tarczy 2πr/4
r=30 cm
s=droga=?
s=droga=2*π*30/4cm
s=15π[cm]
π=3,14
π=47,1cm