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dane: V1=0,5dm3 H2O, d=1g/cm3, V2=1,12dm3 Cl2, Mcl2=71g/mol
szukane: cp Cl2
71g Cl2....................22,4dm3
x..........................1,12dm3
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x = 71g*1,12dm3/22,4dm3 = 3,55g Cl2
masa wody = 500cm3*1g/cm3 = 500g
cp = 3,55g*100%/503,55g = 0,7%
0trzymana woda chlorowa była 0,7
.....................pozdrawiam