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r alas kerucut = 7 cm
Ditanyakan luas selimut = ....?
Volume kerucut = 1 . phi . r² . t
3
1.232 cm³ = 1 . 22 . 7 cm . 7 cm . t
3 7
56 cm² = 1 . 7 cm . t
3
8 cm = 1 . t
3
t = 8 cm . 3
t = 24 cm
s = √ r² + t²
s = √ 7² + 24²
s = √ 49 + 576
s = √ 676
s = 26 cm
maka, Luas selimut kerucut = phi . r . s
= 22 . 7 cm . 26 cm
7
= 22 . 26 cm²
= 572 cm²