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p:l:t=5a:3a:9a
maka
v=p.l.t
8680=5a.3a.9a
8680=135a pangkat 3
a pangkat 3=8680/135
apangkat 3=64,2
a=4
p=5a=5.4=20
l=3a=3.4=12
t=9a=9.4=36
maka luas permukaan balok =2(p.t+l.t)+(p.l)
=2(20.36+12.36)+20.12
=2(720+432)+240
=2.1152+240
=2304+240
=2544cm persegi