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---------= ½√2
F + F
√(F² + F² + 2 F F cos(180-α))
--------------------------------------... = ½√2
√(F² + F² + 2 F F cosα)
√(F² + F² - 2 F F cosα)
-------------------------------- = ½√2.....note:cos(180-α)= -cosα
√(F² + F² + 2 F F cosα)
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2 F² - 2 F² cosα
------------------------ = ½
2 F² + 2 F² cosα
2 F² - 2 F² cosα = F² + F² cosα
2 F² - F² = 2 F² cosα + F² cosα
F² = 3 F² cosα
cosα = 1/3
α = 70 derajat
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