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y2 = 4
y1 = y2
2√x = 4
(2√x)² = 4²
4x = 16
x = 4
batas int x =0 dan x = 4
Volume = π₀⁴∫y2² - y1² dx
Volume = π₀⁴16 - 4x dx
Volume = π[16x - 2x²]⁴₀
Volume = π[16(4) - 2(16)] = 32 π