Question

(11V3-4V7/V3-V7) - (13V7 +V3/V12-V28)
V pierwiastek

Answer 1

(11√3-4√7)/(√3-√7)-(13√7+√3)/(√12-√28)=
(11√3-4√7)(√3+√7)/(3-7)-(13√7+√3)(√12+√28)/(12-28)=
(11*3+11√3*√7-4√7*√3-4*7)/-4-(13√7*√12+13√7*√28+√3*√12+√3*√28)/-16=
(33+11√21-4√21-28)/-4-(13√84+13√196+√36+√84)/-16=
(5+7√21)/-4-(14√84+13√196+√36)/-16=
(5+7√21)-(14√84+13*14+6)/-4=
(5+7√21)-[14√(4*21)+182+6]/-4=
(5+7√21)-(28√21+188)/-4=
(5+7√21)-4(7√21+47)/-4=
5+7√21+7√21-47=
-42+14√21