December 2018 1 16 Report
Uzasadnij równość dla dowolnego kąta ostrego :
a ) cos²α · (tg²α + 1) = 1
cos²α · ( \frac{sin ^{2} }{cos ^{2} } +1) = 1
( \frac{sin ^{2} }{cos ^{2} } +1) = 1 - cos²α
 \frac{sin ^{2} }{cos ^{2} } +1 = sin²α

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