November 2018 1 23 Report

uzasadnij że równość jest tożsamością trygonometryczną

1)  \frac{tg\alpha} {1+tg^{2}}=sin\alpha*cos\alpha

2)sin\alpha*(1+\frac{1}{sin\alpha}+ctg\alpha)+(1-\frac{1}{sin\alpha}+ctg\alpha)=2cos\alpha

3)\frac{cos\alpha-ctg\alpha}{ctg\alpha}=sin\alpha-1

4)(sin\alpha+tg\alpha)(cos\alpha-ctg\alpha)=(sin\alpha-1)*(cos\alpha+1)sin\alpha=(\frac{1}{sin\alpha}=ctg\alpha)(1-cos\alpha)


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