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Cn+1H2n+4 -- kolejny alkan
Za n podstawiam masy atomowe:
12n+2n+2 / 12n+12+2n+4 = 1 / 1,467
14n+2 / 14n+16 = 1/1,467
14n+16 = 1,467(14n+2)
14n+16 = 20,538n+2,934
13,066 = 6,538n
n = 2
Pierwszy alkan: C₂H₆
Drugi alkan: C₃H₈