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39u + 16u + 1u = 56u
b) HNO3
1u + 14u + 3*16u = 15u+48u = 63u
KOH
m cz=39+16+156=u
b) kwas azotowy (V)
HNO3
m cz=1+14+ 3*16=63u
Mcz = 39 + 16 + 1 = 56u
b) wzór: HNO₃
Mcz = 1 + 14 + 3*16 = 63u
Pozdrawiam ;p