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(2-x)³-2x(x-1)(x+3)-(1+x²)x=
=2³-3*2²*(-x)+3*2*(-x²)-x³-2x(x²+3x-x-3)-(x+x³)=
=8-3*4*(-x)+6*x²-x³-2x³-6x²+2x²+6x-x-x³=
=8+12x+6x²-x³-2x³-6x²+2x²+6x-x-x³=
=-x³-2x³-x³+6x²-6x²+2x²+12x+6x-x+8=
=-4x³+2x²+17x+8
jak coś nie jasne to pisz:))