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kedua = n+2
ketiga = n+4
n+n+2+n+4 = 54
3n + 6 = 54
3n = 54-6
3n = 48
n = 48/3
n = 16
kedua = n+2 = 18
ketiga = n+4 = 20
Jumlah = 20+16 = 36
x-2+x+x+2= 54
3x = 54
x = 54/3
= 18
jadi barisannya = 16,18,20
jumlah terbesar dan terkecil = 16+20 = 36