Question

Tolong dibantu yaaa makasiih.... no 25

Answer 1

Verified answer

Jawab

ᵇlog a = - 2 --> a = b⁻²

³log b = ³log 2 { 1 + ²log 4a}

³log b = ³log 2 { ²log 2 + ²log 4(b⁻²)}
³log b = ³log 2.²log 8b⁻²
³log b = ³log 8b⁻²

b = 8b⁻²
b³ = 8
b = 2

a = b⁻² = (2)⁻² = 1/4

4a + b = 4 (1/4) + 2
4a + b = 3

Answer 2

Verified answer

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^3log b = ^3log 2 (1 + ²log 4a)
^3log b = ^3log 2 + ^3log 2 . ²log 4a
^3log b = ^3log 2 + ^3log 4a
^3log b = ^3log (2 . 4a)
^3log b = ^3log 8a
b = 8a

^blog a = -2
a = b^-2
a = (8a)^-2
a = 1/64a²
a . a² = 1/64
a = ^3√(1/64)
a = 1/4

b = 8 . a
b = 8 . 1/4
b = 2

4a + b
= 4 . 1/4 + 2
= 1 + 2
= 3

✩✩ A ✩✩