" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
l = lo.(1 + λ.ΔT)
Donde: l = Longitud final
lo = longitud inicial
λ = Coeficiente de dilatacion del material
ΔT = Cambio de temperatura
Para nuestro caso
lo = 100 m
ΔT = (T final - T inicial) = (24°C - 8°C) = 16°C (Se expande)
λ = 1.2 x 10^-5 [°C^-1]
l = 100m[1 + (1.2 x 10^-5 °C^-1)(16 °C)]
l = 100m[1 + 0.000192]
l = 100m[1.000192]
l = 100.0192 m
Medira: 100.0192 m
osea que se expande 19.2 mm