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d1=50m
t=3s
d2=100m
Vi=0
Solución
d=Vi.t+1/2at^2
50=1/2a(3)^2
50=1/2a(9)
a=(2x50)/9
a=100/9
a =11.11m/s^2
Tiempo en recorrer 100m
d=Vi.t+1/2at^2
d=1/2at^2
t=√[2d]/a
t=√[2(100)]/11.11
t=√[200]/11.11
t=√18
t=4.24s
Saludos.....