Question

umie ktoś proporcje i rozwiąze mi chociaz te które umie ;

-5(a-y+1)=

6ab(a-b+3)=

-(x-4+5y)=

-(x-2)+(y-3)=

7(x+a)-2(x-a)=

5(ab+b-1)-ab=

4(x-y)-2(x-y)

6a(a-2)+2(a do potegi 2 -a)=

(4a-2b)-6a-(7b-8)=

3a-(4b+18)+5a+9=

5a-(4a do potegi 2 + b-a)+ (a do potegi 2 -7)=

(3a-6b)-(4a+8b)-(9a-2b)=

Answer 1

-5(a-y+1)= -5a+5y-5

6ab(a-b+3)= 6ab - 6ab + 18 ab

-(x-4+5y)=-x+4x-5xy

-(x-2)+(y-3)=-x+2x+y-3=x+y-3

7(x+a)-2(x-a)=7x+7a-2x+2a=5x+9a

5(ab+b-1)-ab=5ab+5b-5-ab=4ab+5b-5

4(x-y)-2(x-y)= 4x-4y-2x+2y=2x-2y

6a(a-2)+2(a do potegi 2 -a)= 6a-12a + 2a-2a=8a-14a

(4a-2b)-6a-(7b-8)= 4a-2b-6a+7b+8=-2a+5b+8