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Verified answer
P(1,3) dan Q(3,1)PQ = diameter lingkaran
PQ = √((1 - 3)² + (3 - 1)²)
PQ = 2√2
jari2 lingkaran = √2
titik tengah PQ adalah pusat lingkaran.
P(x,y)
x = (1 + 3)/2 = 2
y = (3 + 1)/2 = 2
Persamaan lingkaran dg P(2,2) dan jari2 = √2
(x - 2)² + (y - 2)² = (√2)²
(x - 2)² + (y - 2)² = 2