rozwiąż równania:
a)x/3-x/2=2
b)(x-2)(x+3)=x^
^-do kwadratu
/-ułamek
prosze o szybkaodp.daje naj
b)
(x-2)(x+3)=x^
x^+3x-2x-6=x^
x^-x^+x=6
x=6
a)x/3-x/2=2 |*3
x- 3 x/2=6 |*2
2x-6x=12
-4x=12 |: (-4)
x=-3
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b)
(x-2)(x+3)=x^
x^+3x-2x-6=x^
x^-x^+x=6
x=6
a)x/3-x/2=2 |*3
x- 3 x/2=6 |*2
2x-6x=12
-4x=12 |: (-4)
x=-3