prosze o pomoc
napisz rownanie prostej, do ktorej nalezą punkty
1.) A = ( 0 , - 4) , B = (3 , - 6 )
2.) A = ( - 3 , - 8 ) , B = ( 1 , - 8 )
odpowiedzi do zad1
y = - 2/3 x - 4
zad 2
y = - 8
2/3 / ułamek
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y = ax + b
-4 = 0 + b /* -1
-6 = 3a + b
4 = 0 - b
-6 = 3a + b
-2 = 3a
a = - 2/3
4 = 0 - b
b = -4
y = -2/3x - 4
-8 = -3a + b
-8 = a + 3b /*3
-8 = -3a + b
-24 = 3a + 3b
-32 = 4b / : 4
b = - 8
- 8 = - 3a - 8
-3a = 0
a = 0
y = 0x - b
y = -8
y=ax+b
1.) A = (0,-4) , B=(3,- 6)
-4=b
-6=3a+b
-4=b
-6=3a-4
-4=b
3a=-2 /:3
b=-4
a=-2/3
y=-2/3x-4
2.) A=(-3,-8) , B=(1,-8)
-8=-3a+b
-8=a+b /*(-1)
-8=-3a+b
8=-a-b
-4a=0
a=0
a=0
b=-8-a
a=0
b=-8
y=-8