August 2018 2 10 Report
Które równanie ma nieskonczenie wiele rozwiązań?
a)-3(x-5)=2i1/2(8-4x)
b)0,5x-3i1/2=-4(7/8-0,125x)
c)5(1,2x-1i1/4)=-9x+3i3/4
d)-4[-4(-4+3x)+3x]+3x=-(x+4)
e)3x-2(4i1/2-4x)+1=x-2(1-5x)-6
f)2x/7+3x/14+4x/21-x/42-0,5=x-2(1/4+x/6)
/-ułamek

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