Tylko c, d, e, f z poziomu D, E Plis daje 90 punktów. Tylko z zamienianiem na ułamki o tych samych m.... Question from @kubacw221

$D.\\\\c) \ \frac{1}{6}+0,5 = \frac{1}{6}+\frac{1}{2} = \frac{1}{6}+\frac{3}{6} = \frac{4}{6} = \frac{2}{3}\\\\d) \ \frac{1}{5}+0,6 = \frac{1}{5}+\frac{6}{10} = \frac{1}{5}+\frac{3}{5} = \frac{4}{5}\\\\e) \ \frac{3}{8} + 0,1 = \frac{3}{8}+\frac{1}{10} = \frac{15}{40}+\frac{4}{40} = \frac{19}{40}$

$f) \ 0,12 + \frac{1}{25} = \frac{12}{100} + \frac{1}{25} = \frac{3}{25}+\frac{1}{25} = \frac{4}{25}$

$E.\\\\c) \ 0,1 + \frac{4}{26}+\frac{11}{13} = \frac{1}{10}+\frac{2}{13}+\frac{11}{13} =\frac{1}{10}+\frac{13}{13} = \frac{1}{10}+1 = 1\frac{1}{10}\\\\d) \ 0,25+0,17+\frac{3}{4}+0,03 = 0,45+\frac{3}{4} = \frac{45}{100}+\frac{3}{4} = \frac{9}{20}+\frac{15}{20} = \frac{24}{20} = 1\frac{4}{20} = 1\frac{1}{5}$

$e) \ 0,2+\frac{2}{17}+\frac{4}{5} = \frac{2}{10}+\frac{2}{17}+\frac{4}{5} = \frac{1}{5}+\frac{4}{5}+\frac{2}{17} = \frac{5}{5}+\frac{2}{17} =1+\frac{2}{17} = 1\frac{2}{17}$

$f) \ 0,82+\frac{2}{8}+0,28} = 0,82+0,28}+\frac{1}{4}=1,1 + \frac{1}{4} = \frac{11}{10} + \frac{1}{4} = \frac{22}{20}+\frac{5}{20} = \frac{27}{20} = 1\frac{7}{20}$

3 votes Thanks 1

kubacw221 a poziom e?

basetla Skoro zgłosiłeś, to nie mam możliwości dopisania (nie zauważyłam, że poziom E też)

c) (-5)x(-1)-5.x(-2) (-5)x(-3) 5.x (-4) - (-5)x(-5)

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c) (-5)x(-1)-5.x(-2) (-5)x(-3) 5.x (-4) - (-5)x(-5)​

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c) (-5)x(-1)-5.x(-2) (-5)x(-3) 5.x (-4) - (-5)x(-5)