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f'(x) = 3(6x-3)^2 .6 (2x-1) + (6x-3)^3(2)
f'(1) = 3(6.1-3)^2 .6(2.1-1) + (6.1-3)^3 .2
= 18(27) + 27.2
= 540
= 18 (6x-3)^2 (2x-1) + 2(6x-3)^3
=36x-16(6x-3)^3