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Verified answer
TuRunaNf(x)= (6x + 3)² (2x - 1)
f(x) = u(x). v(x)
u(x)= (6x + 3)²
u' (x) = 2(6)(6x + 3) = 12(6x + 3)
v(x) = (2x - 1)
v '(x) = 2
f(x) = u(x). v(x)
f '(x) = u'(x) , v(x) + u(x) . v'(x)
f'( x) =12 (6x+3)(2x-1) + (6x+3)² (2)
f'(x) = (6x+3) { 12 (2x -1) + 2(6x + 3)}
f'(x) = (6x + 3) ( 24x -12 + 12 x + 6 )
f'(x)= (6x+ 3) ( 36 x - 6)
f'(x) = (6x+ 3)(6)(6x -1)
f'(x)= 6(6x+3)(6x-1)
f'(x)= 6(3)(2x+1)(6x-1)
f'(x)= 18(2x+1)(6x-1)
f'(x) = 18 (12x² +4x -1)