tu są dwa zadania w załączniku proszę o pomoc !!
a)
b)
c)
d)
e)
f)
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a)![\sqrt[3]{\frac{1}{64}}+\sqrt{16}+\frac{3}{4^{2}}=\frac{1}{4}+4+\frac{3}{16}=4\frac{3}{16}+\frac{4}{16}=4\frac{7}{16} \sqrt[3]{\frac{1}{64}}+\sqrt{16}+\frac{3}{4^{2}}=\frac{1}{4}+4+\frac{3}{16}=4\frac{3}{16}+\frac{4}{16}=4\frac{7}{16}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B64%7D%7D%2B%5Csqrt%7B16%7D%2B%5Cfrac%7B3%7D%7B4%5E%7B2%7D%7D%3D%5Cfrac%7B1%7D%7B4%7D%2B4%2B%5Cfrac%7B3%7D%7B16%7D%3D4%5Cfrac%7B3%7D%7B16%7D%2B%5Cfrac%7B4%7D%7B16%7D%3D4%5Cfrac%7B7%7D%7B16%7D)
b)
c)![\sqrt[3]{8^{2}-3^{2}+(-3)^{2}}=\sqrt[3]{64-9+9}=\sqrt[3]{64}=4 \sqrt[3]{8^{2}-3^{2}+(-3)^{2}}=\sqrt[3]{64-9+9}=\sqrt[3]{64}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%5E%7B2%7D-3%5E%7B2%7D%2B%28-3%29%5E%7B2%7D%7D%3D%5Csqrt%5B3%5D%7B64-9%2B9%7D%3D%5Csqrt%5B3%5D%7B64%7D%3D4)
d)
a)
b)![6\cdot2^{2}-3^{3}=6\cdot4-9=24-9=15 \\\sqrt[3]{125}+4^{0}=5+1=6 \\15>6 6\cdot2^{2}-3^{3}=6\cdot4-9=24-9=15 \\\sqrt[3]{125}+4^{0}=5+1=6 \\15>6](https://tex.z-dn.net/?f=6%5Ccdot2%5E%7B2%7D-3%5E%7B3%7D%3D6%5Ccdot4-9%3D24-9%3D15+%5C%5C%5Csqrt%5B3%5D%7B125%7D%2B4%5E%7B0%7D%3D5%2B1%3D6+%5C%5C15%3E6)
c)![\sqrt[3]{729}-3^{2}=9-9=0 \\5^{1}+(-1)^{3}=5+(-1)=4 \\0<4 \sqrt[3]{729}-3^{2}=9-9=0 \\5^{1}+(-1)^{3}=5+(-1)=4 \\0<4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729%7D-3%5E%7B2%7D%3D9-9%3D0+%5C%5C5%5E%7B1%7D%2B%28-1%29%5E%7B3%7D%3D5%2B%28-1%29%3D4+%5C%5C0%3C4)
d)
e)
f)