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52=3*10+b
52=30+b
b=22
h² =10² -6²
h² =100-36
h² =64
h=8
P=1/2[(a+b)*h]
P=1/2[(10+22)*8]
P=1/2[32*8]
P=1/2[256]
P=128 jednostek²
Odp: Pole tego trapezu wynosi 128 j²
Pozdrawiam ^^
XD