Question

Trygonometria - zadanie w załączniku

Answer 1

 

tgα = 2/5

 

tgα = sinα/cosα

sinα/cosα = 2/5 => sinα = 2/5cosα

 

sin²α + cos²α = 1

(2/5cosα)² + cos²α = 1

4/25cos²α + cos²α = 1

29/25cos²α = 1

cos²α = 25/29

cosα = 5/√29 lub cosα = -5/√29

 

sinα = 5/2 * 5/√29 lub sinα = 5/2 * (-5/√29)

sinα = 25/2√29 lub sinα = -25/2√29

 

sinα = 25√29/58 lub sinα = -25√29/58

cosα = 5√29/29 lub cosα = -5√29/29

tgα = 2/5

ctgα = 1/tgα = 5/2

 

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Litterarum radices amarae sunt, fructus iucundiores

 

Pozdrawiam :)