Trojkat o obwodzie 50cm podzielono na dwa trojkaty o obwodach 30cm i 56cm.Ile wynosi dlugosc tej wysokosci trojkata?
30cm+56cm-2h=50cm
-2h=50cm-30cm-56cm
-2h=-36cm /:(-2)
h=18cm
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30cm+56cm-2h=50cm
-2h=50cm-30cm-56cm
-2h=-36cm /:(-2)
h=18cm