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Zatem:
(a+b)*h/2 = 3x*h, gdzie:
a-krotsza podstawa trapezu
b- dluzsza podstawa trapezu
h-wysokosc trapezu i rombu
x-bok rombu
więc:
a+b=6x =>b=6x-a
stosunek dłuższej podstawy trapezu(b) do boku rombu(x):
(6x-a)/x = 6-a/x