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= S (f,3)
f (x) = x² - x +
= Ф
⇒ g (x) = x² +1
f (x) = x² - x = (B (I,(R), d2)
g(x) = x² +1≈ r = √ (2R - h)h
= x ∈ D ⇒ g(x) = x² +1
=(B (I,(R), d2)