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n(S) = 36
Kejadian jumlah mata dadu 4
(K1) = (1,3)(2,2)(3,1)
n(K1) = 3
Kejadian jumlah mata dadu 8
(K2) = (2,6)(3,5)(4,4)(5,3)(6,2)
n(K2) = 5
Peluang
P(K1∪K2) = P(K1) + P(K2) - P(K1∩K2)
P(K1∪K2) = n(K1)/n(S) + n(K2)/n(S) - 0
P(K1∪K2) = 3/36 + 5/36
P(K1∪K2) = 8/36
P(K1∪K2) = 2/9
Peluangnya adalah 2/9
n(S) = 36
Kejadian jumlah mata dadu 4
(K1) = (1,3)(2,2)(3,1)
n(K1) = 3
Kejadian jumlah mata dadu 8
(K2) = (2,6)(3,5)(4,4)(5,3)(6,2)
n(K2) = 5
Peluang
P(K1∪K2) = P(K1) + P(K2) - P(K1∩K2)
P(K1∪K2) = n(K1)/n(S) + n(K2)/n(S) - 0
P(K1∪K2) = 3/36 + 5/36
P(K1∪K2) = 8/36
P(K1∪K2) = 2/9
Peluangnya adalah 2/9