Question

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Answer 1

10. Anggap :

1/x = a , 1/y = b , 1/z = c

a+2b+3c = 8

2a+2b+4c = 10 <= a+b+2c = 5 (1)

2a+4b+2c = 4 <= a+2b+c = 2 (2)

a+2b+c = 2 <= tambah kedua ruas dengan c

a+2b+2c = 2 + c <= a+b+2c = 5 <= a+2b+2c = 5+b

5+b = 2 + c

c - b = 3 (3)

a+2b+3c = 8 <= a+2b+c = 2 , a+2b+3c = 2+2c

2+2c = 8

2c = 6

c = 3 (4)

1/z = 3

z = 1/3

c - b = 3

3 - b = 3

b = 0 (5)

1/y = 0 , y = 0

a+2b+c = 2 <= b = 0 , c = 3

a+2.0+3 = 2

a + 3 = 2

a = -1

1/x = -1 , x = -1

x = -1 , y = 0 , z = 1/3

x+3z = -1 + 3.1/3

        = -1 + 1

x+3z  = 0