Question

TOLONG BANGETTT DONGGGGGGG.

Answer 1

(x + y)(x + y + z) = 40
(x + z)(x + y + z) = 32
(2 + x)(x + y + z) = 24

sama2 dikali (x + y + z)

faktor persekutuan dari 40, 32 dan 24 adalah 8, maka (x + y + z) = 8

(x + y)(8) = 40
x + y = 5

(x + z)(8) = 32
x + z = 4

(2 + x)(8) = 24
(2 + x) = 3

2 + x = 3
x = 3 -2
x = 1

x + z = 4
1 + z = 4
z = 4 - 1
z = 3

x + y = 5
1 + y = 5
y = 5 - 1
y = 4

maka,
3x + 2y - z
= 3(1) + 2(4) - 3
= 3 + 8 - 3
= 8