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L = Lo + Lo.α.ΔT
50,012 = 50 + 50x0,000012x(T-28))
50,012 - 50 = 50x0,000012 (T-28)
0,012 = 0,0006 (T-28)
T-28 = 0,012 / 0,0006
T-28 = 20
T = 20+28
T = 48°C
T1 = 28°C
L1 = 50 cm
α = 0,000012/°C
L2 = 50,012 cm
Ditanya : T2 ?
Jawab :
Pertama, cari perubahan panjang besi (ΔL)
ΔL = L2 - L1 = 50,012 - 50 = 0,012 cm
Lalu, hitung T2 dengan rumus
T2 = ( ΔL / (L1 x α) + T1
T2 = ( 0,012cm / ( 50cm x 0,000012/°C ) + 28°C
T2 = (0,012 / 0,0006) + 28°C
T2 = 20 + 28
T2 = 48°C
Jadi, besi tersebut dipanaskan sampai suhu 48°C. (D)
Moga membantu :)