Question

Tolong ya no 12
makasih

Answer 1

M = 0.7 kg
C = 4200 J = 1 KKal/Kg . celcius
t1 = 22 celcius
t2 = 100 celciu
delta T = (t2 - t1) = 100 - 22 = 78 celcius

Q = M . C . T
Q = (0.7 Kg) . (1 Kkal /Kg.Celcius) . (78 celcius) = 5.46 Kkal (b)

Answer 2

M = 0,7 kg= 700 g
c = 1 kal/g°C
Δt = 100-22 = 78 C

Q = m.c.Δt = 700x1x78 = 54.600 kal = 54,6 kkal