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b = 4
c = (p+2)
αβ² + βα² = - 20
(αβ)(α + β) = - 20
{(p+2)/(p-2)}{ -4/ (p-2) } = -20
-4(p+2) / (p-2)² = - 20
-20(p-2)² = -4 (p+2)
5(p² - 4p + 4) = p + 2
5p² - 20p + 20 = p + 2
5p² - 21p + 18 = 0
(5p-6)(p-3)= 0
p = 6/5 atau p = 3