Question

Tolong nomer 16 sama 19 pliss

Answer 1

16 M=n/v
1=n/0,3
n=0,3
m=nxmr
=0,3x64
=19,2

19 mol Fe =m/mr 5,6×10^6/56=10^5 
Fe2O3  + 3CO-->  2Fe  +  3CO2
5x10^4                  10^5

mFe2O3=nxmr
=5x10^4 x160
=8x10^6