Question

tolong no 25 ... pakai caranya

Answer 1

AP : PB = 2: 3
3 AP = 2 PB
3(p-a)= 2(b-a)
3p - 3a = 2b - 2a
3p = 2b - 2a + 3a
3p = 2b + a
3p  = 2(5,0,1)+(2, -3, 4) = (12, -3, 6)
p = (4, -1 , 2)

PC = c-p = (4, 2, 5) - (4, -1, 2) = (0, 3, 3)
panjang PC = √(0²+3²+3²) = √(18) = 3√2