" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
27^(3x-1)/4 = 9^(x+2)/2
3^ [3(3x-1)/4] = 3^[2(x+2)/2]
.
3(3x-1)/ 4 = 2(x+2) /2
(9x-3) / 4 = (2x+4)
(9x-3) = 4(2x+4)
9x-3 = 8x + 16
9x - 8x = 16+3
x = 19
.
2)
7'log 2 = a , 2'log 3 = b
7'log 2 . 2'log 3 = 7'log 3 = ab
6'log 98 = 7'log 98 / 7'log 6 = (7'log7^2 + 7'log2)/(7'log 3+7'log 2)
= (2 + a)/(ab+ a)