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= (³^³log3² + ²log2² x ³^½log3¹)/(³log(2/18))
= (⅔ x ³log3 + 2 x ²log2 + 1/½ x ³log3)/(³log3-²)
= (⅔ + 2 + 2)/-2
= (4⅔)/-2
= 14/3 x (-½)
= - 14/6
jawaban : B