Question

Tolong kerja nomor 11 dong. Makasih sebelumnya. Tolong tulis caranya juga ya.

Answer 1

Sin A= 4/5, maka tan A = 4/3

tan (60+A) - tan (60-A)
= (tan 60+tan A)/(1-tan 60.tan A) - (tan 60-tan A)/(1+tan 60.tan A)
= (√3+(4/3))/(1-√3.(4/3)) - (√3-(4/3))/(1+√3.(4/3))
= ((√3+(4/3))(1+√3.(4/3)) - (√3-(4/3))(1-√3.(4/3)))/(1-√3.(4/3))(1+√3.(4/3))
= ((√3+4+(4/3)+(9/16).√3) - (√3-4-(4/3)+(9/16).√3))/(1-(16/3))
= (8+(8/3))/(-13/3)
= -32/13
= -96/39..........opsi B