y= 3x + 2 --> m1 = 3
syarat grs tegak lurus
m1 x m2 =-1
3 x m2 = -1
m2= - 1/3
grs melalui (6,-1) dgn m = -1/3
y - y1= m (x - x1)
y-(-1) = - 1/3 (x - 6)
y+1 = - 1/3 x +2
y = - 1/3 x +2 -1
y = - 1/3 x + 1 --> dikali 3
3y = -1 x + 3
3y + x = 3
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y= 3x + 2 --> m1 = 3
syarat grs tegak lurus
m1 x m2 =-1
3 x m2 = -1
m2= - 1/3
grs melalui (6,-1) dgn m = -1/3
y - y1= m (x - x1)
y-(-1) = - 1/3 (x - 6)
y+1 = - 1/3 x +2
y = - 1/3 x +2 -1
y = - 1/3 x + 1 --> dikali 3
3y = -1 x + 3
3y + x = 3