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x² + x - 3 = 0
x² + x = 3 X4 (kedua ruas dikali 4)
4x² + 4x = 12 +1 (kedua ruas dijumlah dng 1)
4x² + 4x + 1 = 13
= 13
(2x + 1) = +/-
2x = -1 +/-
x =
x =
x1 =
x2 =
2xkuadrat+2x=6
xkuadrat+x=3
xkuadrat+x+(1\2.1)kuadrat=3+(1/2.1)kuadrat
(x+1/2.1)kuadrat=3+(1/2.1)kuadrat
x+1/2=akar13/4
x=-1/2plusminus akar13/2
apa yang seperti ini?