Question

Tolong jawab soal nomer 13 yaa

Answer 1

Sin a = 1/√3
Dengan:
y = 1
r = √3
Maka:
x = √[r²-y²]
x = √3-1
x = √2

Sehingga:
cosec a . tg a
= 1/sin a . sin a/cos a
= 1/cos a
= 1/(x/r)
= r/x
= √3/√2
Rasionalisasi:
= √3/√2 . √2/√2
= √6/2 [C]