khosteep81
Massa C = 28,6% = 28,6 gr massa H = 4,8% = 4,8 gr massa N = 66,6% = 66,6 gr perbandingan mol C : H : N = 28,6/12 : 4,8/1 : 66,6/14 = 2,38 : 4,8 : 4,76 = 1 : 2 : 2 rumus empirisnya = CH2N2
Mr = bj x R x T / P = 1,72 x 0,082 x (25+273) / 1 Mr = 42,763
(CH2N2) n = 42,76 (12 + 1(2) + 14(2) )n = 42,763 42n = 42,763 n = 1
massa H = 4,8% = 4,8 gr
massa N = 66,6% = 66,6 gr
perbandingan mol C : H : N =
28,6/12 : 4,8/1 : 66,6/14 = 2,38 : 4,8 : 4,76 = 1 : 2 : 2
rumus empirisnya = CH2N2
Mr = bj x R x T / P = 1,72 x 0,082 x (25+273) / 1
Mr = 42,763
(CH2N2) n = 42,76
(12 + 1(2) + 14(2) )n = 42,763
42n = 42,763
n = 1
rumus molekul diazometana = CH2N2
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