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2. L = 12 × 8
10 + x = 96
x = 96 - 10 = 86 vm
L EFGH = 12 × 8 = 96 cm^2
L ABCD = 12 × 20 = 240 cm^2
3.
Lbce = 1/2 × 8 × 15 = 60cm^2
L layang = 36
d1 = AC = 6
Dit : BC =?
jawab :
saya menambahkan titik O di tengah diagonal AC dan BD
AO = OC = 3
BO = OD = 6
2. Diket : L kecil = 10 + x
lebar kecil = gf = 8 cm
pjg kecil = ef = 12 cm
pjg besar = ab = 20 cm
lebar besar = bc = 12 cm
a) nilai x
jawab :
b) luas EFGH =?
jawab :
Luas EFGH = 10 + x = 10 + 59 = 69 cm2
c) luas ABCD = ?
jawab :
Luas ABCD = pjg besar × lebar besar
Luas ABCD = 20 cm × 12 cm
Luas ABCD = 240 cm2