Question

Tolong dong, kerjain soal berikut! (kesetimbangan larutan)... 20 poin

Answer 1

Verified answer

CaF2 ---> Ca2+ + 2F-
2.10-4 ~ 2.10-4 ~ 4.10-4
ksp = [Ca2+] [F-]2
= (2.10-4) (4.10-4)2
= 32.10-12
= 3,2.10-11

jawaban B

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Answer 2

Verified answer

Materi : Hasil Kali Kelarutan

CaF2 <====> Ca2+ + 2 F-
s mol . s mol . 2 s mol

dgn s = 2×10^-4 M

Ksp = [Ca2+].[F-]^2
= 2×10^-4 . (4×10^-4)^2
= 32×10^-12

Jawaban B.

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