#F
lim(x->0) (x² -1) sin6x / (x³+3x + 2)
substitusi x = 0
= (-1 sin 0)/(2)
= 0/2
= 0
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#F
lim(x->0) (x² -1) sin6x / (x³+3x + 2)
substitusi x = 0
= (-1 sin 0)/(2)
= 0/2
= 0